PHP实现数组根据某个字段进行水平合并，横向合并案例分析_php技巧_

 Array ( [0] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [1] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [3] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 ) ) 

 Array ( [0] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) [1] => Array ( [date] => 2019-05-11 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) ) 

 Array ( [2019-04-02] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [2019-04-09] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2019-05-05] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [2019-05-11] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) [2019-05-07] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) ) 

 $total = array_merge($a,$b)); $res = array(); foreach ($total as $k => $v) { if (empty($res[$v['date']])) $res[$v['date']] = $v; else $res[$v['date']]= array_merge($res[$v['date']],$v); }